count = [0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]

order = "yes"

index = -1

end = 0

keywords = ["1","2","3","4","5","6","1","1","1",",",",",",",".",".",",",

",",",",",",",",","]

i = 0

while order == "yes" or order == "YES":

keywords[i] = input("input the keyword\n")

i = i + 1

end = end + 1

order = input("continue?yes^\n")

for keyword in keywords:

index += 1

j = 0

with open("C:\\Users\\Administrator\\Desktop\\1.txt") as file:

for i in file:

for A in i:

if keyword[j] == A:

j = j + 1

else:

j = 0

if j == len(keyword):

count[index] += 1

j = 0

file.close()

for index in range(0,end):

print(keywords[index] + " " +str(count[index]))

不管這個關鍵詞是好的還是差的，我相信你不需要去數不需要去計算就能感覺到，數過以後計算過以後只能是你自己騙自己的一個牽強的理由！如果關鍵詞是貶義詞，那你就給自己一個牽強的微笑吧！一笑而過比什麼都好，要哭就躲在被窩裡哭個夠吧！如果是好的關鍵詞，我相信你就偷著樂吧，因為不需要你去計算你也能明白對方想表達的含義！