可以使用以下方式：1、使用迴圈，把每一位數字轉換成相應的字元，參考程式碼如下：#include <stdio.h>#include <string.h> int main(){ int num, n, i = 0; char str[20], tmp[20]; scanf("%d", &num); n = num % 10; while (n>0) { tmp[i++] = n + "0"; num = (num - n) / 10; n = num % 10; } tmp[i] = "\0"; for (i=0; i<=strlen(tmp)-1; i++) { str[i] = tmp[strlen(tmp)-i-1]; } str[i] = "\0"; printf("%s\n", str); return 0;}2、使用庫函式，程式碼如下：#include <stdio.h>#include <string.h> int main(){ int num; char str[20]; scanf("%d", &num); itoa(num, str, 10); printf("%s\n", str); return 0;}