#用enumerate函式，最好不要用index ，因為列表有相同的元素的時候，index就傻冒了for i,j in enumerate(("a","b","c")): print i,j 0 a1 b2 c

1.

a=["a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n"]

b=[1,4,3,6,10]

c = type(a)(map(lambda i:a[i], b)) #這裡沒有判斷 b的元素作為a的索引的時候 值太大 溢位的異常

print c

>>>

["b", "e", "d", "g", "k"]

>>>

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2.

>>> import numpy as np

>>> b = np.array([2,3,4,5,6])

>>> a = np.array([0,2,4])

>>> b[a]

array([2, 4, 6])