select username,count(*) as count from hk_test group by username having count>1;
SELECT username,count(username) as count FROM hk_test GROUP BY username HAVING count(username) >1 ORDER BY count DESC;
這種方法只是統計了該欄位重複對應的具體的個數
場景二:列出username欄位重複記錄的具體指:
1
2
3
4
5
select * from hk_test where username in (select username from hk_test group by username having count(username) > 1)
SELECT username,passwd FROM hk_test WHERE username in ( SELECT username FROM hk_test GROUP BY username HAVING count(username)>1) 但是這條語句在mysql中效率太差,感覺mysql並沒有為子查詢生成臨時表。在資料量大的時候,耗時很長時間
解決方法:
場景三:檢視兩個欄位都重複的記錄:比如username和passwd兩個欄位都有重複的記錄:
1
2
select * from hk_test a
where (a.username,a.passwd) in (select username,passwd from hk_test group by username,passwd having count(*) > 1)
場景四:查詢表中多個欄位同時重複的記錄:
1
select username,passwd,count(*) from hk_test group by username,passwd having count(*) > 1
MySQL裡查詢表裡的重複資料記錄:
先檢視重複的原始資料:
場景一:列出username欄位有重讀的資料
1
2
3
select username,count(*) as count from hk_test group by username having count>1;
SELECT username,count(username) as count FROM hk_test GROUP BY username HAVING count(username) >1 ORDER BY count DESC;
這種方法只是統計了該欄位重複對應的具體的個數
場景二:列出username欄位重複記錄的具體指:
1
2
3
4
5
select * from hk_test where username in (select username from hk_test group by username having count(username) > 1)
SELECT username,passwd FROM hk_test WHERE username in ( SELECT username FROM hk_test GROUP BY username HAVING count(username)>1) 但是這條語句在mysql中效率太差,感覺mysql並沒有為子查詢生成臨時表。在資料量大的時候,耗時很長時間
解決方法:
場景三:檢視兩個欄位都重複的記錄:比如username和passwd兩個欄位都有重複的記錄:
1
2
select * from hk_test a
where (a.username,a.passwd) in (select username,passwd from hk_test group by username,passwd having count(*) > 1)
場景四:查詢表中多個欄位同時重複的記錄:
1
select username,passwd,count(*) from hk_test group by username,passwd having count(*) > 1
引數說明:
user_name為要查詢的重複欄位.
count用來判斷大於一的才是重複的.
user_table為要查詢的表名.
group by用來分組
having用來過濾.