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  • 1 # 秘魯比

    套用公式:1^2+2^2+3^2+4^2+5^2………………+n^2=n(n+1)(2n+1)/6。

    1^2+2^2+3^2+4^2+5^2………………+100^2=100×101×201÷6=338 350。

    擴充套件資料:

    常用平方數:

    1² = 1, 2² = 4 ,3² = 9, 4² = 16, 5² = 25, 6² = 36 ,7² = 49 ,8² = 64 ,9² = 81 ,10² = 100

    11² = 121, 12² = 144 ,13² = 169 ,14² = 196 ,15² = 225, 16² = 256, 17² = 289 ,18² = 324, 19² = 361 ,20² = 400

    21² = 441 ,22² = 484, 23² = 529 ,24² = 576, 25² = 625 ,26² = 676, 27² = 729 ,28² = 784 ,29² = 841, 30² = 900

    相關公式:

    (1)1+2+3+.+n=n(n+1)/2

    (2)1^2+2^2+3^2+...+n^2=n(n+1)(2n+1)/6

    (3)1×2+2×3+3×4+4×5+…+n(n+1)

    =(1^2+1)+(2^2+2)+(3^2+2)+...+(n^2+n)

    =(1^2+2^2+...+n^2)+(1+2+3+.+n)

    =n(n+1)(2n+1)/6+n(n+1)/2

    =n(n+1)(n+2)

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