回覆列表
  • 1 # Mnbcxs

    >> Ke = [2 1;1 2];m = 10;K = zeros(m+1,m+1);for p = 1:m k = zeros(m+1,m+1); k(p:p+1,p:p+1) = Ke; K = K+k;end;>> KK = 2 1 0 0 0 0 0 0 0 0 0 1 4 1 0 0 0 0 0 0 0 0 0 1 4 1 0 0 0 0 0 0 0 0 0 1 4 1 0 0 0 0 0 0 0 0 0 1 4 1 0 0 0 0 0 0 0 0 0 1 4 1 0 0 0 0 0 0 0 0 0 1 4 1 0 0 0 0 0 0 0 0 0 1 4 1 0 0 0 0 0 0 0 0 0 1 4 1 0 0 0 0 0 0 0 0 0 1 4 1 0 0 0 0 0 0 0 0 0 1 2

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