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  • 1 # hyhpe7905

    (1)橢圓過點(√6,1),∴6/a^2+1/b^2=1.離心率c/a=1/√2,∴a^2=2c^2,b^2=c^2,代入上式得4/c^2=1,c^2=4,a^2=8,∴橢圓的標準方程是x^2/8+y^2/4=1.(2)設A(2√2cosu,2sinu),B(2√2cosv,2sinv),則向量PA*PB=(2√2cosu-√6,2sinu-1)*(2√2cosv-√6,2sinv-1)=(2√2cosu-√6)(2√2cosv-√6)+(2sinu-1)(2sinv-1)=8cosucosv-4√3(cosu+cosv)+6+4sinusinv-2(sinu+sinv)+1=-2,∴8cosucosv+4sinusinv-4√3(cosu+cosv)-2(sinu+sinv)+9=0,①AB的斜率=(sinu-sinv)/[√2(cosu-cosv)],AB的方程是y-2sinu=(sinu-sinv)(x-2√2cosu)/[√2(cosu-cosv)],設AB過定點(m,n),則√2(cosu-cosv)(n-2sinu)=(sinu-sinv)(m-2√2cosu),∴√2(cosu-cosv)n-(sinu-sinv)m+2√2(sinucosv-cosusinv)=0.②不存在常數m,n,使得方程①、②同解,∴AB不過定點.

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