專案中遇到後臺傳給前臺的json字串命名方式不符合java的命名規範如：{"exp_value":"exp1","user_age":11,"user_name":"username1"}javabean中是小駝峰命名：

private String userName;

private String expValue;

private int userAge

關於FastJson屬性別名的問題，網上很多文章都指出@JSONField(name = "***")必須要註解在setter和getter上面;但是實際測試compile "com.alibaba:fastjson:1.1.56"版本的FastJson發現@JSONField註解其實可以直接寫到屬性名上面，例項如下：

JavaBean

public class JsonTestBean {

@JSONField(name = "user_name")

private String userName;

@JSONField(name = "exp_value")

private String expValue;

@JSONField(name = "user_age")

private int userAge;

public String getExpValue() {

return expValue;

}

public void setExpValue(String expValue) {

this.expValue = expValue;

}

public int getUserAge() {

return userAge;

}

public void setUserAge(int userAge) {

this.userAge = userAge;

}

public String getUserName() {

return userName;

}

public void setUserName(String userName) {

this.userName = userName;

}

@Override

public String toString() {

return "JsonTestBean{" +

"expValue="" + expValue + "\"" +

", userName="" + userName + "\"" +

", userAge=" + userAge +

"}";

}

}

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Test方法:

@org.junit.Test

public void jsonTest() {

JsonTestBean jsonTestBean = new JsonTestBean();

jsonTestBean.setUserName("username1");

jsonTestBean.setExpValue("exp1");

jsonTestBean.setUserAge(11);

System.out.println("bean->json : " + JsonUtils.toJson(jsonTestBean));

String jsonStr = "{\"exp_value\":\"exp2\",\"user_age\":22,\"user_name\":\"username2\"}";

JsonTestBean toBean = JsonUtils.toBean(jsonStr, JsonTestBean.class);

if (toBean != null) {

System.out.println("json-> bean : " + toBean.toString());

}

}

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執行結果:

bean->json : {"exp_value":"exp1","user_age":11,"user_name":"username1"}

json-> bean : JsonTestBean{expValue="exp2", userName="username2", userAge=22}

可以發現@JSONField是可以放在屬性上面的