解:3.9x7.7+3.9x1.4+3.9等於( 3939/100 ),【即等於39.39】
∵已知需求出3.9x7.7+3.9x1.4+3.9等於多少
X × (Y + Z)= X × Y + X × Z
∴3.9 x 7.7 + 3.9 x 1.4 + 3.9
= 3.9 × (7.7 + 1.4 + 1)
= (3×10+9)/10 × [(7×10+7)/10+(1×10+4)/10+1]
= 39/10 × (77/10 + 14/10 + 10/10)
= 39/10 × (91/10 + 10/10)
= 39/10 × 101/10
= 3939/100
= 39.39
答:3.9x7.7+3.9x1.4+3.9等於3939/100,【即等於39.39】
解:3.9x7.7+3.9x1.4+3.9等於( 3939/100 ),【即等於39.39】
∵已知需求出3.9x7.7+3.9x1.4+3.9等於多少
X × (Y + Z)= X × Y + X × Z
∴3.9 x 7.7 + 3.9 x 1.4 + 3.9
= 3.9 × (7.7 + 1.4 + 1)
= (3×10+9)/10 × [(7×10+7)/10+(1×10+4)/10+1]
= 39/10 × (77/10 + 14/10 + 10/10)
= 39/10 × (91/10 + 10/10)
= 39/10 × 101/10
= 3939/100
= 39.39
答:3.9x7.7+3.9x1.4+3.9等於3939/100,【即等於39.39】