回覆列表
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1 # 落洛的小仙女
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2 # v哈哈7
print("%s呼叫了雜湊方法"%self.name) return hash(id(self)
) def __eq__(self, other)
: print("%s呼叫了eq方法"
) if self.__dict__ == other.__di
print("%s呼叫了雜湊方法"%self.name) return hash(id(self)
) def __eq__(self, other)
: print("%s呼叫了eq方法"
) if self.__dict__ == other.__di
方法一: 使用內建set方法來去重
>>> lst1 = [2, 1, 3, 4, 1]
>>> lst2 = list(set(lst1))
>>> print(lst2)
[1, 2, 3, 4]
方法二: 使用字典中fromkeys()的方法來去重
>>> lst1 = [2, 1, 3, 4, 1]
>>> lst2 = {}.fromkeys(lst1).keys()
>>> print(lst2)
dict_keys([2, 1, 3, 4])
方法三: 使用常規方法來去重
>>> lst1 = [2, 1, 3, 4, 1]
>>> temp = []
>>> for item in lst1:
if not item in temp:
temp.append(item)
>>> print(temp)
[2, 1, 3, 4]
方法四: 使用列表推導來去重
>>> lst1 = [2, 1, 3, 4, 1]
>>> temp = []
>>> [temp.append(i) for i in lst1 if not i in temp]
[None, None, None, None]
>>> print(temp)
[2, 1, 3, 4]
方法五: 使用sort函式來去重
>>> lst1 = [2, 1, 3, 4, 1]
>>> lst2.sort(key=lst1.index)
>>> print(lst2)
[2, 1, 3, 4]
方法六: 使用sorted函式來去重
>>> lst1 = [2, 1, 3, 4, 1]
>>> lst2 = sorted(set(lst1), key=lst1.index)
>>> print(lst2)
[2, 1, 3, 4]