回覆列表
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1 # 老生談笑
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2 # Sunny魯寧
y=tanx
y"=sec²x
所以y""=2secx*(secx)"
=2secx*secxtanx
=2sec²xtanx
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3 # 使用者0451花園
(tan²x)′=2tanx(tanx)′
=2tanx(sinx/cosx)′
=2tanx×(cosxcosx+sinxsinx)/cos²x
=2tanx/cos²x。
y = ln( tan(x/2) )"= 1/( tan(x/2) ) * ( tan(x/2) )"= 1/( tan(x/2) ) * ( sec^2(x/2) ) * (x/2)"= 1/( tan(x/2) ) * ( sec^2(x/2) ) * (1/2)= 1/( 2tan(x/2)*sec^2(x/2) )