金屬單質（Na，Al）的還原性

2Na+H2===2NaH

4Na+O2===2Na2O

2Na2O+O2===2Na2O2

2Na+O2===Na2O2

2Na+S===Na2S（爆炸）

2Na+2H2O===2NaOH+H2

2Na+2NH3===2NaNH2+H2

4Na+TiCl4（熔融）===4NaCl+Ti

2Al+3Cl2===2AlCl3

4Al+3O2===2Al2O3（鈍化）

4Al(Hg)+3O2+2xH2O===2(Al2O3.xH2O)+4Hg

4Al+3MnO2===2Al2O3+3Mn

2Al+Cr2O3===Al2O3+2Cr

2Al+Fe2O3===Al2O3+2Fe

2Al+3FeO===Al2O3+3Fe

2Al+6HCl===2AlCl3+3H2

2Al+3H2SO4===Al2(SO4)3+3H2

2Al+6H2SO4(濃)===Al2(SO4)3+3SO2+6H2O

(Al,Fe在冷,濃的H2SO4,HNO3中鈍化)

Al+4HNO(稀)===Al(NO3)3+NO+2H2O

2Al+2NaOH+2H2O===2NaAlO2+3H2

不穩定性:

2Al(OH)3===Al2O3+3H2O

酸性:

2NH3+2Na==2NaNH2+H2

(NaNH2+H2O===NaOH+NH3) 2Al + 2NaOH + 2H2O === 2NaAlO2 + 3H2(上升)

2FeCl3+2Al+3H2O=2Fe(OH)3+3H2+2AlCl3

2al + 3h2so4 === al2(so4)3 + 3h2↑ 鋁稀鹽酸反應：2al + 6hcl === 2alcl3 + 3h2↑

Al+4HNO3=Al(NO3)3+NO↑+2H2O

2 AlCl3 + 3 K2CO3 + 3 H2O===6 KCl + 2 Al(OH)3 + 3 CO2

AlCl3 + 3NaOH === Al(OH)3↓ +3NaCl

Al(OH)3 + NaOH === NaAlO2 + 2H2O

2Al + 2NaOH + 2H2O === 2NaAlO2 + 3H2↑

AlCl3 + 3NaAlO2 +6H2O === 4Al(OH)3↓

AlCl3 + 3NaHCO3 === Al(OH)3↓ + 3CO2↑ +3NaCl

反應1:2AL+6H2O=2AL(OH)3+3H2,

反應2:AL(OH)3+NaOH=NaALO2+2H2O

所以總的反應為:2Al + 2NaOH + 2H2O === 2NaAlO2 + 3H2